A Carnot engine takes 3 × 10 6 cal of heat from a reservoir at 627ºC and gives it to a sink at 27ºC. The work done by the engine is:
Text Solution
Verified by ExpertsThe correct answer is:
B
T 1 = 627 + 273 = 900K
Q 1 = 3 × 10 6 cal
T2 = 27 + 273 = 300K
∴ 
Q 2 = 
× Q 1 = 
× 3 × 10 6
= 1× 10 6 cal
Work done = Q 1 – Q 2
= 3 × 10 6 –1 ×10 6 = 2 ×10 6 cal
= 2 × 4.2 × 10 6 J = 8.4 × 10 6 J
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